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Q. A magnetized straight wire has magnetic moment $M$. it is bent into semi circular arc its magnetic moment becomes

Solution:

$M^{1}=\frac{2 M \sin \left(\frac{\theta}{2}\right)}{\theta}$
$M^{1}=\frac{2 M \sin \left(\frac{\pi}{2}\right)}{\pi}$
$M^{1}=\frac{2 M}{\pi}$