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Q. A machine gun fires six bullets per second into a target. The mass of each bullet is $3 g$ and the speed $500\, m / s$. The power delivered to the bullets is

Work, Energy and Power

Solution:

The power delivered is the work done per second which again is equal to the total kinetic energy of the six bullets fired per second.
Hence power $P=6$ (kinetic energy of each bullet)
$=6\left[\frac{1}{2} \times 3 \times 10^{-3} \times(500)^{2}\right] J / s$
$ =2250\, W =2.25\, kW$