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Q.
A machine gun fires a bullet of mass $40 \,g$ with a velocity $1200 \,ms ^{-1}$. The man holding it can exert a maximum force of $144 \,N$ on the gun. How many bullets can he fire per second at the most
Solution:
$u=$ velocity of bullet
$\frac{d m}{d t}=$ Mass fired per second by the gun
$\frac{d m}{d t}=$ Mass of bullet $\left(m_{B}\right) \times$ Bullets fired per sec $(N)$
Maximum force that man can exert $F=u\left(\frac{d m}{d t}\right)$
$\therefore F=u \times m_{B} \times N$
$\Rightarrow N=\frac{F}{m_{B} \times u}$
$=\frac{144}{40 \times 10^{-3} \times 1200} $
$=3$