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Q. A long straight wire of radius $R$ carries a current $i$ . The magnetic field inside the wire at distance $r\left(\right.r < R\left.\right)$ , from its centre is expressed as

NTA AbhyasNTA Abhyas 2020Moving Charges and Magnetism

Solution:

Using Ampere's law, we have
$\oint \overset{ \rightarrow }{B}.\overset{ \rightarrow }{d l}=\mu _{0} \, i_{i n}$
Solution
or $B\times 2\pi r=\mu _{0}\frac{i}{\pi R^{2}}\pi r^{2}$
$\therefore $ $B=\frac{\mu _{0}}{2 \pi }.\frac{i r}{R^{2}}$