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  4. A long solenoid of N turns has a self-inductance L and area of cross-section A. When a current i flows through the solenoid, the magnetic field inside it has magnitude B, The current is equal to

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Q. A long solenoid of $N$ turns has a self-inductance $L$ and area of cross-section $A$. When a current $i$ flows through the solenoid, the magnetic field inside it has magnitude $B$, The current is equal to

Solution:

$N \phi=L I$
$N B A=L I$
$I=\frac{N B A}{L}$