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Q. A long horizontal rod has a bead which can slide along its length, and initially it is at a distance $L$ from the end $A$ of the rod. The rod is set in angular motion about $A$ with constant angular acceleration $\alpha $ in a gravity free space. If the coefficient of friction between the rod and the bead is $\mu $ , then the time after which the bead starts slipping is

NTA AbhyasNTA Abhyas 2020Laws of Motion

Solution:

$N=m\alpha L$
When the bead starts slipping
$f_{\max}=\mu N=m\omega ^{2}L$
$\mu m\alpha L=m\left(\alpha t\right)^{2}L$
$\Rightarrow t=\sqrt{\frac{\mu }{\alpha }}$
Solution