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Q. A long, hollow conducting cylinder is kept coaxially inside another long, hollow conducting cylinder of larger radius. Both the cylinders are initially electrically neutral.

JEE AdvancedJEE Advanced 2007

Solution:

Let $\lambda$ be the charge density on the inner cylinder.
For $a < r < b$, we get
$ E =\frac{\lambda}{2 \pi \varepsilon_{0} r} $
$\Delta V =-\frac{\lambda}{2 \pi \varepsilon_{0}} \int\limits_{a}^{b} \frac{d r}{r}=\frac{\lambda}{2 \pi \varepsilon_{0}} \ln \left(\frac{a}{b}\right)$
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Hence, a potential difference appears between the two cylinders when a charge density is given to the inner cylinder.