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Q. A line is drawn through the point P(3, 11) to cut the circle $x^2 + y^2 = 9$ at A and B. Then $PA \cdot PB$ is equal to

Conic Sections

Solution:

Given circle, $x^2 + y^2 = 9$
image
$PA\times PB = PT ^{2}\quad$ [ By Geometry]
$PA \times PB = \left(3\right)^{2} + \left(11\right)^{2} - 9 = 121$