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Q. A light string passes over a frictionless pulley. To one of its ends a mass of $10 kg$ is attached to its other end a mass of $15 kg$ is attached. The tension in the thread will bePhysics Question Image

Laws of Motion

Solution:

$T =\left(\frac{2 m _{1} m _{2}}{ m _{1}+ m _{2}}\right) g $
$=\frac{2 \times 10 \times 15 \times 9.8}{25}$
$T =\frac{2 \times 2 \times 15 \times 9.8}{5}=117.6 N$