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  4. A light string passes over a frictionless pulley. To one of its ends a mass of 6 kg is attached. To its other end a mass of 10 kg is attached. The tension (in newton) in the thread will be [Take g = 9.8 m/s2] <img class=img-fluid question-image alt=image src=https://cdn.tardigrade.in/img/question/physics/08edc4f44299e24dbce037729585932c-.png />

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Q. A light string passes over a frictionless pulley. To one of its ends a mass of $6$ kg is attached. To its other end a mass of $10$ kg is attached. The tension (in newton) in the thread will be [Take $g = 9.8$ m/s$^{2}$]
image

Laws of Motion

Solution:

$T= \frac{2m_{1}m_{2}}{m_{1} +m_{2}}g$
$= \frac{2 \times 10\times 6}{10 +6} \times9.8 = 73.5N$