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  4. A light ray is incident to a line mirror ' L ' along the line 3 x-4 y+5=0 and is reflected along the line 5 x-12 y+19=0. The equation of line 'L' may be

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Q. A light ray is incident to a line mirror ' $L$ ' along the line $3 x-4 y+5=0$ and is reflected along the line $5 x-12 y+19=0$. The equation of line 'L' may be

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Solution:

$ \frac{3 x-4 y+5}{5}= \pm \frac{5 x-12 y+19}{13}$
$\Rightarrow 7 x+4 y-15=0$ and $4 x-7 y+10=0$