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Q. A lift is going up. The total mass of the lift and the passenger is $1500\, kg$ . The variation in the speed of the lift is as given in the graph. The tension in the rope pulling the lift at $t = 11th$ sec will be
image

Laws of Motion

Solution:

At $11$ th second lift is moving upward with acceleration
$a=\frac{0-3.6}{2}$
$=-1.8 \,m/s^{2}$
Tension in rope, $T=m(g-a)$
$1500(9.8-1.8) = 12000\,N$