Question

A junction diode is connected to a 10 V source and $10^3\,\Omega$ resistor as shown in figure. The slope of load line on the characteristic curve of diode will be

• A. $10^{-2}\, A\, V^{-1}$
• B. $10^{-3}\, A\, V^{-1}$
• C. $10^{-4}\, A\, V^{-1}$
• D. $10^{-5}\, A\, V^{-1}$

Answer 1

Answer: (B)

If V is the voltage across the junction and $I$ is the circuit current, then
$V + IR = E$ or $I = \frac{E}{R} -\frac{V}{R} = -\frac{V}{R} +\frac{E}{R}$
Slope of load line $= − \frac{1}{R} = \frac{1}{1000} = 10^{-3} \,A\,V^{-1}$