Question

A junction diode has a resistance of 25 Ω when forward biased and 2500 Ω when reverse biased. The current in the diode, for the arrangement shown will be

• A. $\frac{1}{15}A$
• B. $\frac{1}{7}A$
• C. $\frac{1}{25}A$
• D. $\frac{1}{180}A$

Answer 1

Answer: (B)

The junction diode is forward biased. Therefore, the effective resistance
$=25+10=35\, \Omega$
$\therefore $ Current in diode $I=\frac{5\, V }{35\, \Omega}=\frac{1}{7} A$