1. Tardigrade
  2. Question
  3. Chemistry
  4. A hypothetical reaction A2+B2→ 2AB follows the mechanism as given below, A2A+A(fast) A+B2 xrightarrowAB+B(slow) A+B xrightarrowAB(fast) The order of the overall reaction is

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Q. A hypothetical reaction $ {{A}_{2}}+{{B}_{2}}\to 2AB $ follows the mechanism as given below, $ {{A}_{2}}A+A(fast) $ $ A+{{B}_{2}}\xrightarrow{{}}AB+B(slow) $ $ A+B\xrightarrow{{}}AB(fast) $ The order of the overall reaction is

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Solution:

From slow step, rate $ =k[{{B}_{2}}][A] $ From 1st equation $ {{K}_{eq}}=\frac{{{[A]}^{2}}}{[{{A}_{2}}]} $ or $ [A]=\sqrt{{{K}_{eq}}[{{A}_{2}}]}=K_{eq}^{1/2}A_{2}^{1/2} $ Hence, rate $ =k[{{B}_{2}}]K_{eq}^{1/2}{{[{{A}_{2}}]}^{1/2}} $ $ =k{{[{{A}_{2}}]}^{1/2}}[{{B}_{2}}]. $ Hence, order $ =1\frac{1}{2} $