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  4. A hydrogen like species in fourth orbit has radius 1.5 times that of Bohr’s orbit. In neutral state, its valence electron is in

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Q. A hydrogen like species in fourth orbit has radius 1.5 times that of Bohr’s orbit. In neutral state, its valence electron is in

Structure of Atom

Solution:

$r_{n}=\frac{n^{2} a_{0}}{Z}$

$Z=\frac{n^{2} a_{0}}{r_{n}}=\frac{16 a_{0}}{1.5 a_{0}}=10.67=11$

Thus, $Z=11$

$1 s ^{2} 2 s ^{2} 2 p ^{6} 3 s ^{1}$ valence electron in $3 s$