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Q. A hydrogen atom, initially in the ground state is excited by absorbing a photon of wavelength 980$\mathring A $. The radius of the atom in the excited state, it terms of Bohr radius $a_0$, will be : ($h_c$ = $12500\, eV - \mathring A $)

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Solution:

Energy of photon $ = \frac{12500}{980} = 12.75 eV$
$\therefore $ Electron will excite to $n = 4$
Since $'R' \propto n^2$
$\therefore $ Radius of atom will be $16a_0$