Q. A hydrocarbon $A (C_4H_8)$ on reaction with $HCl$ gives a compound $B (C_4H_9Cl)$, which on reaction with 1 mol of $NH_3$ gives compound $C, (C_4H_{11}N)$. On reacting with $NaNO_2$ and $HCl$ followed by treatment with water, compound $C$ yields an optically active alcohol, $D$ Ozonolysis of ‘$A$’ gives $2$ moles of acetaldehyde. The compound ‘$D$’ is
Amines
Solution: