1. Tardigrade
  2. Question
  3. Chemistry
  4. A hydrocarbon A ( C 4 H 8) on reaction with HCl gives a compound B ( C 4 H 9 Cl ) which on reaction with 1 mol of NH 3 gives compound C ( C 4 H 10 N ) . On reacting with NaNO 2 and HCl followed by treatment with water, compound C yields an optically active compound D. The D is

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Q. A hydrocarbon $A \left( C _{4} H _{8}\right)$ on reaction with HCl gives a compound $B \left( C _{4} H _{9} Cl \right)$ which on reaction with 1 mol of $NH _{3}$ gives compound $C \left( C _{4} H _{10} N \right) .$ On reacting with $NaNO _{2}$ and $HCl$ followed by treatment with water, compound $C$ yields an optically active compound $D$. The $D$ is

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