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  4. A hydraulic automobile lift is designed to lift cars with a maximum mass of 3000 kg The area of cross-sections of the piston carrying the load is 425 cm 2. What maximum pressure would the smaller piston have to bear?

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Q. A hydraulic automobile lift is designed to lift cars with a maximum mass of $3000 \,kg $ The area of cross-sections of the piston carrying the load is $425\, cm ^{2}$. What maximum pressure would the smaller piston have to bear?

Mechanical Properties of Solids

Solution:

Pressure is equally transmitted in the fluid, so the pressure is same for both the pistons.
$P=\frac{F}{A}=\frac{(3000 kg )\left(9.8 ms ^{-2}\right)}{\left(425 \times 10^{-4} m ^{2}\right)}$
$=6.92 \times 10^{5} Nm ^{-2}$