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Q.
A hot air ballon of mass $M$ is descending vertically downward with acceleration $a$. How much mass must be removed to give ballon an upward acceleration of $a$?
UP CPMTUP CPMT 2011
Solution:
Let $F$ be constant upthrust force and $m$ is the removed mass.
Free body diagram for case $(1)$.
$(Mg - F) = Ma \quad ...(i)$
Free body digram for case $(2)$
$F - (M -m)g = (M -m )a \quad ...(ii)$
Adding $(i)$ and $(ii)$, we get
$mg = 2 Ma - ma$
$m(g + a) = 2 Ma$
$m = \frac{2Ma}{(g+a)}$