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Q. A hoop rolls on a horizontal ground without slipping with linear speed $v$. Speed of a particle $P$ on the circumference of the hoop at angle $\theta$ is
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System of Particles and Rotational Motion

Solution:

$v_{p}=\sqrt{v^{2}+v^{2}+2vv\,cos\left(180-\theta\right)}$
$\Rightarrow v_{p}=\sqrt{2v^{2}\left[1-cos\,\theta\right]}$
$=2v\, sin \, \left(\theta/ 2\right)$
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