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Q. A hollow sphere of mass M and radius R is released from height h on a inclined plane. If hollow sphere is rolling without slipping on the inclined then velocity of centre of sphere when it reaches the bottom of inclined plane isPhysics Question Image

Solution:

$M.E_i\,= \, ME_f$
$mgh= \, \frac{1}{2}I_{com}\omega^2+\frac {1}{2}mv^2$
$mgh = \frac {1}{2}\times m R^2\times \frac {2}{3}\times \frac {V^2}{R^2}+\frac{1}{2}mv^2$
$mgh = \frac {5}{6}mv^2\Rightarrow v =$ $\sqrt{\frac{6 gh}{5}}$

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