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Q. A helicopter of mass $2000 \,kg $ rises with a vertical acceleration of $15 \,m$ $s^{-2}.$ The total mass of the crew and passengers is $500\, kg$. Choose the correct statements from the following. (Take$\, g=10\,m \,s^{-2}$)
(i) The force on the floor of the helicopter by the crew and passengers is $1.25\times10^{4} N$ vertically downwards.
(ii) The action of the rotor of the helicopter on the surrounding air is $6.25\times10^{4} N$ vertically downwards.
(iii) The force on the helicopter due to the surrounding air is $6.25\times10^{4} N$ vertically upwards.

Laws of Motion

Solution:

Here, Mass of helicopter, $M=2000 \, kg$
Mass of the crew and passengers, $m=500\, kg$
Vertically upwards acceleration, $a=15 \,m$ $s^{-2}$ $g=10\, m$ $s^{-2}$
(i) Force on the floor by the crew and passengers
$=m \left(g+a\right)$ $=500 \,kg$ $ \left(10+15\right)m$ $s^{-2}$
$=12500 \,N$ $=1.25\times10^{4}N$
It acts vertically downwards.
(ii) Action of the rotor of the helicopter on the surrounding air $=\left(M+m\right)$ $\left(g+a\right)$
$=\left(2000+500\right)kg$ $\left(10+15\right)m$ $s^{-2}$
$=62500\, N$ $=6.25\times10^{4} N$
It acts vertically downwards.
(iii) Force on the helicopter due to the surrounding air is equal and opposite to the action of the rotor of the helicopter on the surrounding air.
$\therefore \quad$ Force on the helicopter due to the surrounding air $=6.25\times10^{4}N.$
It acts vertically upwards.