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Q. A helicopter is flying horizontally at $8 \,m/s$ at an altitude $180 \,m$ when a package of emergency medical supplies is ejected horizontally backward with a speed of $12 \,m/s$ relative to the helicopter. Ignoring air resistance, what is the horizontal distance in $(m)$ between the package and the helicopter when the package hits the ground?

Motion in a Plane

Solution:

Time taken by packet to reach the ground:
$T=\sqrt{\frac{2\times180}{10}}=6s$
Horizontal distance travelled by helicopter in this time
$=8 \times 6 =48\,m$
Velocity of package w.r.t. ground
$=12-8=4\,m/s$ in backward direction
Horizontal distance travelled by package in time,
$T=4 \times 6=24\,m$
So, horizontal distance between them $=48+24=72\,m$