1. Tardigrade
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  3. Physics
  4. A heat flux of 4000 J s -1 is to be passed through a copper rod of length 10 cm and area of cross-section 100 cm 2. The thermal conductivity of copper is 400 W / m ° C. The twoends of this rod must be kept at a temperature difference of

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Q. A heat flux of $4000 J s ^{-1}$ is to be passed through a copper rod of length $10 cm$ and area of cross-section 100 $cm ^{2}$. The thermal conductivity of copper is $400 W / m ^{\circ} C$. The twoends of this rod must be kept at a temperature difference of

Thermal Properties of Matter

Solution:

$ H=\frac{K A \Delta T}{\Delta x}$
$ \Rightarrow \Delta T=\frac{H \cdot \Delta x}{K A}$
$=\frac{\left(4000 Js ^{-1}\right)(0.1 m )}{\left(400 Wm ^{-1}{ }^{\circ} C ^{-1}\right)\left(100 \times 10^{-4} m ^{2}\right)}=100^{\circ} C$