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Q. A healthy adult of height $1.7 \,m$ has an average blood pressure (BP) of $100 \,mm$ of Hg. The heart is typically at a height of $1.3\, m$ from the foot. Take, the density of blood to be $10^3 \,kg/m^3$ and note that $100$ mm of Hg is equivalent to $13.3$ kPa (kilo pascals). The ratio of BP in the foot region to that in the head region is close to

KVPYKVPY 2019Mechanical Properties of Fluids

Solution:

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Pressure at head level $= p_{\text{heart}} - \rho gh$
$= 13.3-10^3 \times 10 \times 0.4$
$= 9.3\, kPa$
Pressure at foot level $= P_{\text{heart}}+ \rho gh$
$= 13.3+ 10^3 \times 10 \times 1.3$
$= 26.3 \,kPa$
So, ratio $= \frac{26.3}{9.3} \approx 2.9$ or $3$