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Q. A hammer of mass 1 kg having speed of $ 50\text{ }m/s, $ hit a iron nail of mass $ 200gm $ . If specific heat of iron is $ 0.105cal/g{{m}^{o}}C $ and half the energy is converted into heat, the raise in temperature of nail is:

Rajasthan PMTRajasthan PMT 1995

Solution:

According to law of conservation heat. $ ms\,\Delta t=\frac{1}{2}\left( \frac{1}{2}m{{\upsilon }^{2}} \right)\times \frac{1}{4.2} $ $ \,\Delta t=\frac{1\times 50\times 50}{0.2\times 4\times 4.2\times 0.105\times {{10}^{3}}}={{7.1}^{o}}C $