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Q. A glass tube of length $ 1.0\, m $ is completely filled with water. A vibrating tuning fork of frequency $ 500 \,Hz $ is kept over the mouth of the tube and the water is drained out slowly at the bottom of the tube. If velocity of sound in air is $ 330\,m{{s}^{-1}}, $ then the total number of resonances that occur will be

KEAMKEAM 2008Waves

Solution:

$ f=\frac{v}{4l} $ or $ l=\frac{v}{4f} $
$ \therefore $ $ {{l}_{1}}=\frac{v}{4{{f}_{1}}}=\frac{330}{4\times 500}=0.165\,m; $
$ {{l}_{2}}=\frac{3v}{4{{f}_{1}}}=3{{l}_{1}}=0.495; $
$ {{l}_{3}}=\frac{5v}{4{{f}_{1}}}=5{{l}_{1}}=0.825\,m $
And $ {{l}_{4}}=\frac{7v}{4{{f}_{1}}}=7{{l}_{1}}=1.155>1\,m $
Therefore, number of resonance = 3.