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Q. A given weak acid $(0.01 M )$ has $p K_{a}=6 $ The $pH$ of the solution is____.

Equilibrium

Solution:

$pH =-\log \sqrt{ CK _{a}}=-\frac{1}{2}\left[\log C +\log K _{a}\right]$

$=\frac{1}{2}\left[-\log C-\log K_{a}\right]=\frac{1}{2}[-\log (0.01)+6]=4$