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Q. A gaseous mixture contains oxygen and nitrogen in the ratio 1:4 by weight. The ratio of their number of molecules is

NTA AbhyasNTA Abhyas 2022

Solution:

Number of moles of $O_{2}=\frac{1}{32}$
and number of mol of $N_{2}=\frac{4}{28}$
So $\frac{\text{Number} \, \text{of} \, \text{molecules} \, \text{of} \, \text{O}_{\text{2}}}{\text{Number} \, \text{of} \, \text{molecules} \, \text{N}_{\text{2}}} \text{=} \frac{\text{Number} \, \text{of} \, \text{mol} \, \text{of} \, \text{O}_{\text{2}}}{\text{Number} \, \text{of} \, \text{mol} \, \text{of} \, \text{N}_{\text{2}}}$
$=\frac{1 / 32}{4 / 28}=\frac{1}{32}\times \frac{28}{4}$
$=\frac{7}{32}=7:32$