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Chemistry
A gaseous hydrocarbon gives upon combustion 0.72 g of water and 3.08 g of CO2. The empirical formula of the hydrocarbon is
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Q. A gaseous hydrocarbon gives upon combustion $0.72\, g$ of water and $3.08\, g$ of $CO_2$. The empirical formula of the hydrocarbon is
JEE Main
JEE Main 2013
Some Basic Concepts of Chemistry
A
$C_2H_4$
31%
B
$C_3H_4$
13%
C
$C_6H_5$
11%
D
$C_7H_8$
46%
Solution:
18 g $H_2O$ contains $2g H$
$ \therefore 0.72 \, g \, H_2O$ contains $0.08 \, g \, H$
$44 \, g \, CO_2$, contains $12 \, g \, C$
$ \therefore 3.08 \, g\, CO_2$ contains $0.84 \, g \, C$
$ \therefore \, \, \, \, \, \, \, \, C: H = \frac {0.84}{12}: \frac {0.08}{1}$
$ \, \, \, \, \, = 0.07 : 0.08 = 7:8 $
$ \therefore $ Empirical formula $= C_7H_8$