1. Tardigrade
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  4. A gas occupies 2 litre volume at STP. It is provided 300 joule heat so that its volume becomes 2.5 litre at 1 atm. Change in its internal energy will be

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Q. A gas occupies $2$ litre volume at STP. It is provided $300$ joule heat so that its volume becomes $2.5$ litre at $1$ atm. Change in its internal energy will be

Thermodynamics

Solution:

Work done $=-P \times d V=-1 \times(2.5-2.0)$

$=-1 \times 0.5=-0.5 \text { litre } atm$

$\because$ Work is carried out at constant $P$ and thus irreversible.

$\therefore W =-0.5 \times 101.325\, J (1 \,L\, atm =101.235 J)$

$=-50.66\, J$

From first law of thermodynamics, $q=\Delta E-W$,

$300=\Delta E-(-50.66)$

$300=\Delta E+50.66, \Delta E=249.34 \,J$