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Q. A gas diffuses four times as quickly as oxygen. The molecular weight of gas is:

AFMCAFMC 2002

Solution:

According to rate of effusion or diffusion
$\frac{r_{ O _{2}}}{r_{x}}=\sqrt{\frac{M_{x}}{M_{ O _{2}}}} \left[r_{x}=4 r_{ O _{2}}\right]$
Molecular mass of oxygen $=32$
$\frac{r_{ O _{2}}}{4 r_{ O _{2}}} =\sqrt{\frac{M_{x}}{32}}$
$M_{x} =2$