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Q. A gas cylinder can withstand a pressure of $15\, atm$. The pressure of cylinder is measured $12$ atm at $27^{\circ} C$. Upto which temperature limit the cylinder will not burst?

States of Matter

Solution:

Cylinder will burst at that temperature when it attains the pressure of $15$ atm

$P_{1}=12 atm ; T_{1}=27^{\circ} C =27+273=300 K ; P_{2}=15 atm ; T_{2}=?$

$\frac{P_{1}}{T_{1}}=\frac{P_{2}}{T_{2}} \Rightarrow T_{2}=\frac{15 \times 300}{12}=375 K =(375-273)^{\circ} C =102^{\circ} C$