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  4. A gang capacitor is formed by interlocking a number of plates as shown in figure. The distance between the consecutive plates is 0.885 cm and the overlapping area of the plates is 5 cm2. The capacity of the unit is

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Q. A gang capacitor is formed by interlocking a number of plates as shown in figure. The distance between the consecutive plates is $0.885\, cm$ and the overlapping area of the plates is $5 \,cm^2$. The capacity of the unit isPhysics Question Image

KCETKCET 2006Electrostatic Potential and Capacitance

Solution:

The given arrangement of nine plates is equivalent to the parallel combination of 8 capacitors. The capacity of each capacitor,
$C =\frac{\varepsilon_{0} A}{d} $
$=\frac{8.854 \times 10^{-12} \times 5 \times 10^{-4}}{0.885 \times 10^{-2}}=0.5\, PF$
Hence, the capacity of 8 capacitors
$=8 C=8 \times 0.5=4 \,pF$