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Q. A galvanometer, whose resistance is $50$ ohm, has $25$ divisions in it. When a current of $4 \times 10^{-4}\,A$ passes through it, its needle (pointer) deflects by one division. To use this galvanometer as a voltmeter of range $2.5 \,V$, it should be connected to a resistance of (in ohm)

Moving Charges and Magnetism

Solution:

Galvanometer has 25 divisions
$I_{g} = 4\times 10^{-4} \times 25 =10^{-2}A$
image
$v =I_{g} (G+R)$
$2.5 = (50+R)10^{-2}$
$\therefore R=200\,\Omega$