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Q. A galvanometer of resistance $5$ ohms gives a full scale deflection for a potential difference of $10\, mV$. To convert the galvanometer into a voltmeter giving a full scale deflection for a potential difference of $IV$. the size of the resistance that must be attached to the voltmeter is

Moving Charges and Magnetism

Solution:

$I _{ g }=10 \times 10^{-3} / 5=2 \times 10^{-3} A$
$R =\frac{ V }{ I _{ g }}- R _{ g }=\frac{1}{2 \times 10^{-3}}-5=495\, \Omega$