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Q. A galvanometer having a coil resistance of $30\Omega$ shows full scale defection when a current of $2A$ passes through it. It can be converted into an ammeter to read currents upto $10A$ by :

NTA AbhyasNTA Abhyas 2022

Solution:

$S=\frac{I_{g} R_{g}}{I-I_{q}}=\frac{(2)(30)}{10-2}=\frac{2 \times 30}{8}=\frac{15}{2}=7.5 \Omega$