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Q. A force $(\vec{F})=3 \hat{i}+c \hat{j}+2 \hat{k}$ acting on a particle causes a displacement: $(\vec{s})=-4 \hat{i}+2 \hat{j}+3 \hat{k}$ ' in its own direction. If the work done is $6\, J$, then the value of ' $c$ '. is

Work, Energy and Power

Solution:

$W=(3 \hat{i}+c \hat{j}+2 \hat{k}) \cdot(-4 \hat{i}+2 \hat{j}+3 \hat{k})$
$=6$ joule
$W=-12+2 c+6=6 \Rightarrow c=6$