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Q. A force of magnitude 20 N acts in the direction $4\hat{I}-3\hat{j}$ The force $\hat{F}$ is.

Motion in a Plane

Solution:

Let $\bar{p} = 4 \hat{i} - 3 \hat{j}$ then the required vector can be
$\bar{F} = 20 \, \hat{p} = 20 \frac{(4 \hat{i} - 3 \hat{j})}{(5)} = 16 \hat{i} - 12 \hat{j} \, N$