1. Tardigrade
  2. Question
  3. Physics
  4. A force F =-k(y hat i +x hat j ) where k is a positive constant, acts on a particle moving in the x y plane. Starting from the origin, the particle is taken along the positive x-axis to the point (a, 0) and then parallel to the y-axis to the point (a, a). The total work done by the force on the particle is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A force $F =-k(y \hat{ i }+x \hat{ j })$ where $k$ is a positive constant, acts on a particle moving in the $x y$ plane. Starting from the origin, the particle is taken along the positive $x$-axis to the point $(a, 0)$ and then parallel to the $y$-axis to the point $(a, a)$. The total work done by the force on the particle is

AIIMSAIIMS 2017

Solution:

For the first displacement $y=0$
Hence, $F_{x}=0$ and no work is done.
For the second displacement, $F_{y}=-k a$ and $\Delta y=a$
Work $=F_{y} \Delta y=-k a^{2}$