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  4. A force F = 20 + 10y action a particle in y-direction where F is in newton and y in meter. Work done by this force to move the particle from y = 0 to y = 1 m is :

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Q. A force F = 20 + 10y action a particle in y-direction where F is in newton and y in meter. Work done by this force to move the particle from y = 0 to y = 1 m is :

NEETNEET 2019Work, Energy and Power

Solution:

Work done by variable force is
$W =\int^{y_{f}}_{y_i} Fdy$
Here, $ y_{i} =0, y_{f} = 1m $
$ \therefore W = \int^{1}_{0} \left(20+10y\right)dy$
$ = \left[20y + \frac{10y^{2}}{2}\right]^{1}_{0} = 25J $