Thank you for reporting, we will resolve it shortly
Q.
A flask contains argon and oxygen in the ratio of $3: 2$ in mass and the mixture is kept at $27^{\circ} C$. The ratio of their average kinetic energy per molecule respectively will be :
Average K.E./molecule $=\frac{ f }{2} kT$
So, $\frac{ K _{ Ar }}{ K _{ O _2}}=\frac{\frac{3}{2} KT }{\frac{5}{2} KT }=\frac{3}{5}$
If we consider only translational kinetic energy of a molecule, then
$
\frac{ K _{ Ar }}{ K _{ O _2}}=\frac{\frac{3}{2} kT }{\frac{3}{2} kT }=\frac{1}{1}
$