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Q. A first order reaction is $20\%$ complete in $10$ minutes. What is the specific rate constant for the reaction?

Chemical Kinetics

Solution:

$a-x=\frac{80}{100}\times a=0.8a$, $t=10 \, min$.
$k=\frac{2.303}{t} log$ $\frac{a}{a-x}$ $=\frac{2.303}{10} log$ $\frac{a}{0.8a}$
$k=0.233\, log$ $\frac{10}{8}=0.2303\left(1-0.9030\right)$
$=0.2303\times 0.0970=0.0223$ $min.^{-1}$