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  4. A first order reaction has a rate constant k=3.01 × 10-3 / s. How long it will take to decompose half of the reaction?

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Q. A first order reaction has a rate constant $k=3.01 \times 10^{-3} / s$. How long it will take to decompose half of the reaction?

J & K CETJ & K CET 2012Chemical Kinetics

Solution:

$k=3.01 \times 10^{-3} \,s^{-1}$
$t_{1 / 2}=?$
$k=\frac{0.693}{t_{1 / 2}}$ (for a first order reaction)
$\therefore t_{1 / 2}=\frac{0.693}{k}=\frac{0.693}{3.01 \times 10^{-3}}$