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Q. A fcc crystal contains how many atoms in each unit cell?

Delhi UMET/DPMTDelhi UMET/DPMT 2001

Solution:

$N=\frac{N_{c}}{8}+\frac{N_{f}}{2}+N_{i}$
$=\frac{8}{8}+\frac{6}{2}+0$
$=1+3=4$