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Q. A father with 8 childrens takes them 3 at a time to the zoological gardens, as often as he can without taking the same 3 childrens together more than once. The number of times he will go the garden is

Permutations and Combinations

Solution:

Number of times he will go to garden
$=$ Number of ways of selecting 3 children from 8 children
$={ }^8 C_3=\frac{8 \times 7 \times 6}{3 \times 2}=56$