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Q. A father with $8$ children takes them $3$ at a time to the zoological garden, as often as he can without taking the same $3$ children together more than once. The number of times he will go to the garden is

Permutations and Combinations

Solution:

Number of times he will go to garden
$=$ Number of ways of selecting 3 children from
$8$ children $={ }^{8} C _{3}=\frac{8 \times 7 \times 6}{3 \times 2}=56$