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Q. A factory produces $40\, kg$ of calcium in two hours by electrolysis. How much aluminium can be produced by same current in $2 \,hours$ if current efficiency is $50\%$?

AIIMSAIIMS 2010Electrochemistry

Solution:

$\frac{W_{Ca}}{E_{Ca}}= \frac{W_{Al}}{E_{Al}}$

$\Rightarrow \frac{40}{20}=\frac{W_{Al}}{9}$

$\Rightarrow W_{Al}=18\, kg $

As current efficiency is $50\%$ so, $W_{Al}= 9\, kg$